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Re: WTC Towers: The Case For Controlled Demolition

by BDK <BDK@[EMAIL PROTECTED] > Mar 13, 2008 at 11:12 AM

In article <5870b4a1-0c71-4861-b066-484eaa62c6c2
@[EMAIL PROTECTED]
>, schoenfeld.one@[EMAIL PROTECTED]
 says...
> WTC Towers: The Case For Controlled Demolition
> By Herman Schoenfeld
> 
> In this article we show that "top-down" controlled demolition
> accurately accounts for the collapse times of the World Trade Center
> towers. A top-down controlled demolition can be simply characterized
> as a "pancake collapse" of a building missing its sup****t columns.
> This demolition profile requires that the sup****t columns holding a
> floor be destroyed just before that floor is collided with by the
> upper falling m*****. The net effect is a pancake-style collapse at
> near free fall speed.
> 
> This model predicts a WTC 1 collapse time of 11.38 seconds, and a WTC
> 2 collapse time of 9.48 seconds. Those times accurately match the
> seismographic data of those events.1 Refer to equations (1.9)  and
> (1.10)  for details.
> 
> It should be noted that this model differs massively from a "natural
> pancake collapse" in that the geometrical composition of the structure
> is not considered (as it is physically destroyed).  A natural pancake
> collapse features a dimini****ng velocity rapidly approaching rest due
> to the resistance offered by the columns and surrounding "steel mesh".
> 
> DEMOLITION MODEL
> 
> A top-down controlled demolition of a building is considered as
> follows
> 
> 	1. An initial block of j floors commences to free fall.
> 
> 	2. The floor below the collapsing block has its sup****t structures
> disabled just prior the collision with the block.
> 
> 	3. The collapsing block merges with the momentarily levitating floor,
> increases in mass, decreases in velocity (but preserves momentum), and
> continues to free fall.
> 
> 	4. If not at ground floor, goto step 2.
> 
> 
> Let j be the number of floors in the initial set of collapsing floors.
> Let N be the number of remaining floors to collapse.
> Let h be the average floor height.
> Let g be the gravitational field strength at ground-level.
> Let T be the total collapse time.
> 
> Using the elementary motion equation
> 
>     distance = (initial velocity) * time + 1/2 * acceleration * time^2
> 
> We solve for the time taken by the k'th floor to free fall the height
> of one floor
> 
> 	[1.1]	t_k=(-u_k+(u_k^2+2gh))/g
> 
> where u_k is the initial velocity of the k'th collapsing floor.
> 
> The total collapse time is the sum of the N individual free fall times
> 
> 	[1.2]	T = sum(k=0)^N (-u_k+(u_k^2+2gh))/g
> 
> Now the mass of the k'th floor at the point of collapse is the mass of
> itself (m) plus the mass of all the floors collapsed before it (k-1)m
> plus the mass on the initial collapsing block jm.
> 
> 	[1.3]	m_k=m+(k-1)m+jm =(j+k)m
> 
> If we let u_k denote the initial velocity of the k'th collapsing
> floor, the final velocity reached by that floor prior to collision
> with its below floor is
> 
> 	[1.4]	v_k=SQRT(u_k^2+2gh)
> 
> 
> which follows from the elementary equation of motion
> 
> (final velocity)^2 = (initial velocity)^2 + 2 * (acceleration) *
> (distance)
> 
> Conservation of momentum demands that the initial momentum of the k'th
> floor equal the final momemtum of the (k-1)'th floor.
> 
> 	[1.5]	m_k  u_k  = m_(k-1)  v_(k-1)
> 
> 
> Substituting (1.3) and (1.4) into (1.5)
> 	[1.6]	(j + k)m u_k= (j + k - 1)m SQRT(u_(k-1)^2+ 2gh)
> 
> 
> Solving for the initial velocity u_k
> 
> 	[1.7]	u_k=(j + k - 1)/(j + k) SQRT(u_(k-1)^2+2gh)
> 
> 
> Which is a recurrence equation with base value
> 
> 	[1.8]	u_0=0
> 
> 
> 
> The WTC towers were 417 meters tall and had 110 floors. Tower 1 began
> collapsing on the 93rd floor.  Making substitutions N=93, j=17 , g=9.8
> into (1.2) and (1.7) gives
> 
> 
> 	[1.9]	WTC 1 Collapse Time = sum(k=0)^93 (-u_k+(u_k^2+74.28))/9.8 =
> 11.38 sec
> 		where
> 			u_k=(16+ k)/(17+ k ) SQRT(u_(k-1)^2+74.28)      ;/ u_0=0
> 
> 
> 
> Tower 2 began collapsing on the 77th floor. Making substitutions N=77,
> j=33 , g=9.8 into (1.2) and (1.7) gives
> 
> 
> 	[1.10]	WTC 2 Collapse Time =sum(k=0)^77 (-u_k+(u_k^2+74.28))/9.8 =
> 9.48 sec
> 		Where
> 			u_k=(32+k)/(33+k) SQRT(u_(k-1)^2+74.28)      ;/ u_0=0
> 
> 
> REFERENCES
> 
> "Seismic Waves Generated By Aircraft Impacts and Building Collapses at
> World Trade Center ",
http://www.ldeo.columbia.edu/LCSN/Eq/20010911_WTC/WTC_LDEO_KIM.pdf
> 
> APPENDIX A: HASKELL SIMULATION PROGRAM
> 
> This function returns the gravitational field strength in SI units.
> 
> > g :: Double
> > g = 9.8
> 
> This function calculates the total time for a top-down demolition.
> Parameters:
>   _H - the total height of building
>   _N - the number of floors in building
>   _J - the floor number which initiated the top-down cascade (the 0'th
> floor being the ground floor)
> 
> 
> > cascadeTime :: Double -> Double -> Double -> Double
> > cascadeTime _H _N _J  =  sum [ (- (u k) + sqrt( (u k)^2 + 2*g*h))/g |
k<-[0..n]]
> >                       where
> >                         j = _N - _J
> >                         n = _N - j
> >                         h = _H/_N
> >                         u 0 = 0
> >                         u k = (j + k - 1)/(j + k) * sqrt( (u (k-1))^2
+ 2*g*h )
> 
> 
> Simulates a top-down demolition of WTC 1 in SI units.
> 
> > wtc1 :: Double
> > wtc1 = cascadeTime 417 110 93
> 
> Simulates a top-down demolition of WTC 2 in SI units.
> 
> > wtc2 :: Double
> > wtc2 = cascadeTime 417 110 77
> 

No. It was the Romulans. Using holgraphically enhanced disruptors to do 
the initial damage to the buildings, then they used their special 
tractor beam to shove the towers down. WTC7 was a "lucky hit".

Or, it was the two planes that flew into them, and the fires that came 
as a result.

BDK
 




 1 Posts in Topic:
Re: WTC Towers: The Case For Controlled Demolition
BDK <BDK@[EMAIL PROTEC  2008-03-13 11:12:16 

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tan12V112 Sun Oct 12 5:49:32 CDT 2008.